2-Methyl propyl bromide reacts with C2H5O and gives ‘A’ whereas on reaction with C2H5OH it gives ‘B’. The mechanism followed in these reactions and the products ‘A’ and ‘B’ respectively are :
(1) SN1, A= tert-butyl ethyl ether; SN1, B= 2-butyl ethyl ether
(2) SN2, A= 2-butyl ethyl ether; SN2, B= iso-butyl ethyl ether
(3) SN2, A= iso-butyl ethyl ether; SN1, B= tert-butyl ethyl ether
(4) SN1, A= tert-butyl ethyl ether; SN2, B= iso-butyl ethyl ether

Answer: Option 3
Solution: Strong nucleophiles indicate SN2 reactions while weak nucleophiles indicate SN1 reactions. In above question, C2H5Ois a strong nucleophile (prefers SN2) where as C2H5OH is weak nucleophile (prefers SN1).

2-Methyl propyl bromide reacts with C2H5O– and gives 'A' whereas on reaction with C2H5OH it gives 'B'

Leave a Reply

Your email address will not be published. Required fields are marked *